New deals posted everyday, starting Black Friday and running through the holiday season! No hassles, no lines - just awesome savings on art, deviantWEAR, Premium Memberships and more!
Details
October 25, 2007
197 KB 113 KB 800×1067 StatisticsShare
Link
Embed
Thumb
|
Comments
--
:
E^2= (p^2c^2)+([Δm^2]c^4)
which implies that
E= [mc^2]/[<sq. root>1-(v^2/c^2)]
when p=0 (in eq 1, or in 2 rearranged to 1])
E=mc^2
[as rest mass cannot be attained, p can never=0, so E should, not always be calculated as = mc^2].
--
Member of*TreesClub *Ex-po-zure *MountainShots
[link]
--
www.Qeyd.az
Nice composition, Keep up the good work
--
- .....I'm tired.... -
--
i know my comments are brief, but im not a critic, just an admirer.
new competition - dooo iiiiiiit
feel like a challenge ?
--
...and there is not a single thing here, I can recognize...
Previous Page12345...Next Page